Show the value of the registers RO-R4 after each of the following operations:

Serial	operations
1	R ashr R0
2
3	shr R1+R2
4	ashr R

R0
R1
R2
R3
R4

Sol11:

Assuming that "ashr" stands for arithmetic shift right and "shr" stands for logical shift right, the values of the registers after each operation are:

1. R ? ashr R0

• R0 = (AC30)_H = (1010110000110000)_B
• Performing an arithmetic shift right on R0 gives (D618)_H = (1101011000011000)_B
• Therefore, after this operation: R = (D618)_H

1. R2 ? R0 + R1

• R0 = (AC30)_H = (1010110000110000)_B
• R1 = (0000)_H = (0000000000000000)_B (assuming it is all zeros)
• Adding R0 and R1 gives (AC30)_H = (1010110000110000)_B
• Therefore, after this operation: R2 = (AC30)_H

1. R3 ? shr R1 + R2

• R1 = (0000)_H = (0000000000000000)_B (assuming it is all zeros)
• R2 = (AC30)_H = (1010110000110000)_B
• Adding R1 and R2 gives (AC30)_H = (1010110000110000)_B
• Performing a logical shift right on (AC30)_H gives (5618)_H = (0101011000011000)_B
• Therefore, after this operation: R3 = (5618)_H

1. R4 ? ashr R

• R = (D618)_H = (1101011000011000)_B
• Performing an arithmetic shift right on R gives (E30C)_H = (1110001100001100)_B
• Therefore, after this operation: R4 = (E30C)_H

Therefore, the final values of the registers are:

• R0 = (AC30)_H
• R1 = (0000)_H
• R2 = (AC30)_H
• R3 = (5618)_H
• R4 = (E30C)_H