Question
Show work PART A : Solve the following inequality for xx: e36x14 Answer 1. x=(,3ln146)x=(,3ln146) 2. x=[3ln146,)x=[3ln146,) 3. x=(,3ln146]x=(,3ln146] 4. x=(,0) PART B; Solve the
Show work
PART A : Solve the following inequality for xx:
e36x14 Answer
1. x=(,3ln146)x=(,3ln146)
2. x=[3ln146,)x=[3ln146,) 3. x=(,3ln146]x=(,3ln146]
4. x=(,0)
PART B; Solve the following equation forxx :
log78x+log78(5+112x)=1
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A Graphical Approach To College Algebra
Authors: John E Hornsby, Gary K Rockswold, Margaret K Lial
5th Edition
0321908260, 9780321908261
