show working out please

4) Having reached 5V stored the same capacitor is now discharged through a 22kQ resistor. The Discharging equation for this circuit is: v = Ve where: T = CR and is called the time constant v =the voltage across the capacitor t =the time since the supply voltage applied in seconds C =the capacitance of the capacitor in Farads R =the resistance of the resistor in ohms 3) Calculate the time constant for the circuit. b) Plot the discharging curve of v(vertical) against t(horizontal) over the range 0 to 20 milliseconds. () From your graph use a tangent to the curve to estimate the gradient when t = 7.5ms. d) Differentiate the discharging equation with respect to tand use this to calculate the rate of change of voltage when t = 7.5ms. e) Compare your estimated and calculated answers, is there any difference between the values, why, what could be done to reduce errors? (Hint ensure your gradient and rate of change have the same units)a) Calculate the time constant for the circuit. b) Plot the charging curve of v(vertical) against t(horizontal) over the range 0 to 20 milliseconds. c) Investigate the meaning of 'time constant' and from your graph estimate a value to ensure your graph has been drawn correctly, compare this with your calculated time constant. d) From your graph use a tangent to the curve to estimate the gradient at 3.5ms. e) Differentiate the charging equation with respect to tand use this to calculate the rate of change of voltage when t=3.5ms. f) Compare your estimated and calculated answers, is there any difference between the values, why, what could be done to reduce errors? (Hint ensure your gradient and rate of change have the same units)"four colleague tells you that the operation of a smoothing capacitor depends on its charging and discharging characteristics and these are what you should investigate. They show the results of a simple experiment in which a capacitor was connected in series with a resistor and then charged up from a DC supply. The voltage across the capacitor was measured and displayed on an oscilloscope and then compared with gures derived by calculation. 3]: Here is the information about the circuit Capacitor = 33IZIn F Resistor = 33kt] Supply voltage = sv Charging characteristic for a series capacitive circuit: l: "I.' 1.? V(1 e ) where: T = CH and is called the time constant 19 =the voltage across the capacitor i: =the time since the supply voltage applied in seconds E =the capacitance of the capacitor in Farads H =the resistance of the resistor in ohms