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Showing equivaience trasformation using only few rules. Give to all remodelling steps the used rules = >(Truth) >= (Falsehood) = (Double Negation) = (Contradiction) >=

Showing equivaience trasformation using only few rules.
Give to all remodelling steps the used rules
= >(Truth)
>= (Falsehood)
= (Double Negation)
= (Contradiction)
>= (Redundancy Conjunction)
= (Idempotent Conjunction)
= (Commutativity Conjunction)
( ) = ( ) (Associativity Conjunction)
( ) = ( ) ( ) (Distributivity Conjunction)
= >(Tertium Non Datur)
= (Idempotent Disjunction)
= (Redundancy Disjunction)
= (Commutativity Disjunction)
( ) = ( ) (Associativity Disjunction)
( ) = ( ) ( ) (Distributivity Disjunction)
( ) = (De Morgan 1)
( ) = (De Morgan 2)
= (Implication)
= ( ) ( ) (Equivalence)
(pq)(pq)
I think rhs and lhs both are falsehood but i have no idea left in my head
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