Sign In * Lecture 4.2 - Sam X NKU Imath Asses X StatCrunch X y! you tube - Yahoo x . () Area Under X * Course Hero X + X G https://imath.nku.edu/assessment/showtest.php?action=skip&to=6 Course Forums Calendar Gradebook Log Out Home > STA 205-021 F22, 2nd 7 weeks > Assessment gary steurer HW 4.2: Sampling Distribution of the Sample Mean Due Mon 11/14/2022 11:59 pm Show Intro/ Instructions Questions Black Friday - the annual shopping tradition the day after Thanksgiving - is often the day which puts retailers "in the black." According to a CNN Money report, consumers spent an average of $378.81 on Black Friday in 2010 with a standard deviation of $233.26. Q 1 (0/10) X Q 2 [0/2] a. Draw and label a normal curve which would be used to describe the Black Friday expenditures. Based on the values calculated, would it be reasonable to assume the money spent is Q 3 [2/2] normally distributed? Q 4 (0/4) Q5 (0/8) OIt is not reasonable to assume the amount of money spent by Black Friday shoppers is normally distributed. DQ6 (0/8) It is reasonable to assume the amount of money spent by Black Friday shoppers is normally distributed Q7 (0/8) b. Completely describe the sampling distribution of the sample mean Black Friday expenditure when samples of size 94 are selected. O Q 8 (0/3) . Mean: My = Grade: 2/45 . Standard deviation: og = (round to 4 decimal places) Print Version . Shape:the distribution of y is |Select an answer because Select an answer c. Using the distribution described in part b, what is the probability of observing a sample mean of $450.281 or more? + 0 Z = (round to 2 decimal places) . probability = (include 4 decimal places) d. Based on the probability found, what conclusion can be reached? The probability would be classified as Select an answer v . So, there Select an answer v | sufficient evidence to conclude the mean amount spent by customers on Black Friday is greater than 378.81. Points possible: 8 License This is attempt 1 of 3. Submit 11:27 AM Type here to search O 35F Cloudy ~ $3 9 7 () 11/13/2022