Answered step by step
Verified Expert Solution
Question
1 Approved Answer
Simple Harmonic Motion Introduction: Simple harmonic motion, as shown in Figure 1, is any motion that has a restorative force and forces the object to
Simple Harmonic Motion Introduction: Simple harmonic motion, as shown in Figure 1, is any motion that has a restorative force and forces the object to oscillates indefinitely in the absent of frictional forces. For the case of a mass attached to a spring the restorative force is given by Hooke's law E = kx. m_ ot trarn vl el 1= 47 Pma_lm_bm_ mr=T "'.'IT,'TI'E'U?.'I" Figure 1: l]lustrano-n uf simple harmonic motion for a spring-mass combination at different times, t, of its motion after being released from the x = 4 position. _ Another example of simple harmonic motion is the motion of pendulum where the restorative force is given by F=--mgsinf = mygh mg _ L x_. where the small angle approximation was used to transform the restorative force from a trigonometric function to a linear function in similarity to Hooke's law. The equation of motion for an object - oscillating in simple harmonic motion is g y = Asin{awt + ), Figure 2: lustration of simple harmonic where y is the distance from the equilibrium motion for a pendulum of mass m, position at any time , 4 is the amplitude, or length L, and displacement x. the maximum displacement of the object, and g1is the initial phase angle The oscillatory nature of the simple harmonic motion leads us to compare to circular motion. Therefore the angular frequency can be related to the period of oscillation and the equation of motion can also be expressed as = Asin(2rft) = Asin (ETEJ Laboratory #01: Simple Harmonic Motion where fis the frequency of oscillation and T is the period of oscillation. Further inspection allows us to express the period of oscillation, the frequency of oscillation and the angular speed as function of the spring constant and the mass attached to it: ||m 1 |k k T=2n| = [ = [| Nk f 2 m " m respectively. However it is important to point that springs hardly ever behave as ideal springs. Therefore, in the previous relationships for period, frequency and angular speed we need to use the effective mass of the system, m.y. given by Moy = M panygur + E M gpring Similar expressions can be obtained to describe the oscillation motion of a simple pendulum. L 1 (g T r=2x |- =i _ "J; f =22l ST Equipment Pasco 850 Universal Interface (UL-3000) DMotion sensor 11 (CI-6742) * Spring # Mass hanger with an additional 300 g masses Laboratory #01: Simple Harmonic Motion where fis the frequency of oscillation and T is the period of oscillation. Further inspection allows us to express the period of oscillation, the frequency of oscillation and the angular speed as function of the spring constant and the mass attached to it: ||m 1 |k k T=2n| = [ = [| Nk f 2 m " m respectively. However it is important to point that springs hardly ever behave as ideal springs. Therefore, in the previous relationships for period, frequency and angular speed we need to use the effective mass of the system, m.y. given by Moy = M panygur + E M gpring Similar expressions can be obtained to describe the oscillation motion of a simple pendulum. L 1 (g T r=2x |- =i _ "J; f =22l ST Equipment Pasco 850 Universal Interface (UL-3000) DMotion sensor 11 (CI-6742) * Spring # Mass hanger with an additional 300 g masses Laboratory #01: Simple Harmonic Motion Determination of g Simple Pendulum I. Measure the mass of the metal plumb bob. Construct a simple pendulum 100.0 cm in length using the plumb bob. s a. L is measured from the center of mass of the plumb bob. Move the pendulum from equilibrium to about 20 and release it. Using a stopwatch 3. measure the time required for 5 oscillations. Record measurements in Table 2. I 4. Repeat the previous measurement five more times. 5. Shorten L in increments of 20.0 cm and measure the corresponding f required for ten oscillations. 6. Calculate the average time for ten oscillations for each length. Write results in Table 3. 7. From the average oscillation time determine the period for each length of the pendulum and square period. Record results in Table 3. Table 3 Average f for 5 2 5 8. Create a graph of 72 vs. L. a. Apply a linear trendline to the data to determine its slope. From the slope determine the value of g. and calculate percent error. slope = ear plot have a y-intercept or not? Why
Step by Step Solution
There are 3 Steps involved in it
Step: 1
Get Instant Access to Expert-Tailored Solutions
See step-by-step solutions with expert insights and AI powered tools for academic success
Step: 2
Step: 3
Ace Your Homework with AI
Get the answers you need in no time with our AI-driven, step-by-step assistance
Get Started