Since the hyperbolic functions are defined in terms of exponential functions, it is natural to expect that their inverses should be defined in terms of logarithms. Indeed this is the case; for example, ex -exx sinh x = 2 (i) arcsinh x = log (x + vx2 + 1 xER (ii) a. Derive (ii) from (i). b. Use (i) to show that arccsch x = arcsinh -. c. Use part b. and (ii) to carefully show that - arccsch x - - 1 1x/ V1+x2' making sure to clearly explain where the absolute value comes from