Six balls numbered 1 to 6 are placed in a bag. Some of the balls are grey and some are white. The balls numbered 2 and 5 are grey. The balls numbered 1, 3, 4, and 6 are white. A ball will be selected from the bag at random. The 6 possible outcomes are listed below. Note that each outcome has the same probability. Complete parts (a) through (c). Write the probabilities as fractions. (If necessary, consult a list of formulas.) (a) Check the outcomes for each event below. Then, enter the probability of the event. Outcomes Probability 1 3 4 6. Event A: The selected ball is white Event B: The selected ball has an even number on it Event A or B: The selected ball is white or has an even number on it Event A and B: The selected ball is white and has an even number on it www-awn.aleks.com/alekscgi/x/Isl.exe/1o_u-lgNslkr7j&8P3JH-IBGBIH_OB3uhhqwxlXoS5SIQhuX6YjFjUgDFtG2UWHKIMX7ofvOrmoc7dUZxM-UiO_M_J33DMTTwYPfKWHbvTrEH6EBmGco?1oBw7QYjlbavbSPXtx-YGjsk O PROBABILITY Emmanuel V Outcomes and event probability: Addition rule Outcomes Probability 4 Event A: The selected ball is white Aa Event B: The selected ball has an even number on it Event A or B: The selected ball is white or has an even number on it Event A and B: The selected ball is white and has an even number on it O C O0 O0 (b) Compute the following. P(A) + P (B) P (A and B) = 1 (c) Select the answer that makes the equation true. P(A)+P(B)-P(A and B) = (Choose one) %3D Explanation Check Accessibility 2020 McGraw-Hill Education, All Rights Reserved. Terms of Use Privacy @ ) Type here to search