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Sketch the graph of r= - 13 cos 50. The equation r= - 13 cos 50 is of the form r= a cos n0. Therefore,
Sketch the graph of r= - 13 cos 50. The equation r= - 13 cos 50 is of the form r= a cos n0. Therefore, the graph is a rose. How many petals does the rose have? (Simplify your answer.) What is the length of each petal? unit(s) (Simplify your answer.) At what values of 0 do the endpoints of each petal occur? Since the value of n is odd, give values of 0 on the interval [0,x). Choose the correct answer below. O A. 10 10 2 10 10 OB. 05 5 5'5 I 31 71 91 OC. 5 5 5'5 OD. 05 5 5'5At what values oft) does the graph pass through the pole? Since the value ofn is odd: give values oft] on the interval {0.1:}. Choose the correct answer below. 11 3n n h '31: 10=1U=2=10'10 H 7: 31: T7: 9:: [J B. .1[' 5'5' 55 2x411: 51(8)! Sketch the graph ofr= 13 cos 50. Choose the correct graph below. [:1 A. [:1 Br
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