Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or 5!. Then find the area of the region. 2y=4,y=3, and2y+2rc= Find the area of the region enclosed by y = 3.25: and a: = 7 y2_ Use horizontal strips to find the area, that is, integrate with respect to 3;. First find the 5r coordinates of the two points where y = 3.25: meets :s' = 7 yz. lower limit c = 2. \"[13 v\" -|d'| and upper limit d = m d To find the area of the enclosed region from 1': to d we will integrate: [ g[y]dy where g{ 5r ] = I: Evaluate the definite integral to find Area = -|E| A factory selling cell phones has a marginal cost function C(x) = 0.01x- - 3x + 229, where r represents the number of cell phones, and a marginal revenue function given by R() = 429 -2x. Find the area between the graphs of these curves and > = 0. What does this area represent? O total profit for 200 cell phones sold O total revenue for 200 cell phones sold O total cost for 200 cell phones sold O total profit for more than 200 cell phones soldSet up the definite integral required to find the area of the region between the graph of y = x - 14 and y = 6x - 7. 3+\\sqrt x 12 + 6x +7 V 3-isqrt{ x