Sliding block S M Frictionless surface m Hanging block H VectorStock" Part 1 of 2. For the following system above, with large block S with mass M on the frictionless surface and small block H with mass m suspended by a cable. For the mass M, let the direction right be +x, and the mass m, the direction down is -y. Draw the FBD for each block separately. Write Newton's second law for each, in +x for block S and -y for block H respectively. Hint: Block S has only one force acting on it in +x, block H has two forces acting on it in -y. Also, block S has a normal force FN, but that is in ty, and it is not needed. O E FX = T = Max, E Fy = -T - mg = -may O E FX = T = Max, E Fy = T - mg = -may O E FX = T = max, E Fy = T - Mg = -may O E FX = T = Max, E Fy = T+ mg = -may