Sm 5 370 15m 5. A baseball thrown at an angle of 370 above the horizontal strikes a building 15.0 m away at a point 5.00 m above the point from which it is thrown. Ignore air resistance. a) Find the magnitude of the initial velocity of the baseball (the velocity with which the baseball is thrown). b) What is the time for the baseball takes to strike the building? (rouo c) Find the magnitude of the velocity of the baseball just before it strikes the building. a r = V. Cos ( 37).t > vo: 1/t cos ( 37) M= Vo Sin 37.t- zgth > N: t:cos37 Sin 37.1 - 0.5. 9.862 5=15 tan ( 37) - 4. 96 5:1130- 4.at - 6.3 = - 4.912 6: 129 - 11:30 - 1/30 Vo = Vit cos 37 = 15 /1.29 cos ( 37) = 19.3 m/s = Vo b t : distance t Vox t -. 15 1. 61 m/ 5 9.3 c) Vx : V. Cos 37 Vx : 9. 3 . Cos ( 37) = 7.43 mls = Vx Vy = Vosin 37- gt Vy: 9. 3 sin ( 37) - 9.8 - 1.29 - - 7.05 mls : Vv V= VVx" + Vy = J(7. 432+ (-7.05) 10.24 m/s