So the problem I'm having so I don't understand how we got the answer 2.5 x10^-6 form the equation 0.003 = 27|q| over 0.15^2 . I tried dividing 0.003 by 0.15^2 but it still doesn't give me that 2.5 x 10^-6 answer

Q3: Particle 1 exerts a force on Particle 2 of 0.003 N to the right. What is the sign and magnitude of the charge on Particle2? 15 cm li O O q1=3nC q2_2.5,,ic N* 2 3x10-9c (0.003N)=(9> |q2| = 2.5 >