Soda and lime are added to glass batch in the form of soda ash $(N{a}_{2}C{O}_3)$ and limestone $(CaC{O}_3).$ During heating, these two

ingredients decompose to give off carbon dioxide $(C{O}_2),$ the resulting products being soda and lime$.$ Compute the weight of soda ash

and limestone that must be added to $150l{b}_m$ of quartz $(Si{O}_2)$ to yield a glass of composition $73wt\%Si{O}_2,19w{t}_{m}N{a}_{2}O,$ and $8wt\%$

CaO.

You are to compute the weight $($in $l{b}_m)$ of soda ash and limestone that must be added to a certain amount of quartz to produce a

particular glass composition.First, compute the $l{b}_m$ of both $N{a}_{2}O$ and CaO that is necessary for the particular glass composition

that is given in the problem.

What is the weight in $l{b}_m$ of:

$($a$)N{a}_{2}O$

$!,l{b}_m$

$($b$)$ CaO

$!,l{b}_m$

Finally, convert the $l{b}_m$ of $N{a}_{2}O$ and CaO to the pounds $($mass$)$ of soda ash and lime that will need to be added to the $Si{O}_2.$

What is the weight, in $l{b}_m,$ of $($a$)$ soda ash and $($b$)$ lime that will be added to the $Si{O}_2$ to make the glass outlined in the problem?

$($a$)$

$l{b}_m$

$($b$)$

i

$l{b}_m$