Solubility is often measured in units of $$g$/100$ mL$,$ which is the maximum mass of solute that be dissolved per $100$ mL of solvent to make a saturated solution. The solubility of sodium acetate in water, for example, is $123$ g$/100$ mL$.$

a$)$ Using the solubility given above, calculate the concentration of a saturated sodium acetate concentration as a mass percentage. Assume water has a density of $1\mathrm{.}00$ g$/$mL$.$

b$)$ The supersaturated solution you prepared in Part II used $25$ g of sodium acetate and $20$ mL of water. Express this solution concentration in units of g$/100$ mL$.$

c$)$ Express the concentration of your supersaturated solution as a mass percentage, again assuming the density of water is $1\mathrm{.}00$ g$/$mL$.$