Solution 9. Range of the sample Sample Size =10 Range : Diitemnu between the lowest and highed Valor Range = 8-0 = 8 Sample ' 8 0. 0, 1, 1, 212, 3, 3, 5,83 2) Intequartile range The sample. Median Q2 = 2+2 - 2 , 21 = 1 2 3 = 3 = ( 2, 3, (3 5, 8 ) . Q1 ( 0, 0,01, 2 ) 21 =1 . Interquartile range = $3 - Q1= 3-1 - 2 3 Variant of the Sample Sample Varianc formula 5 2 = [ (x- 8) 2 1 - 1 * = (+0+1+1+ 2+21+3+3+5+8) - 25 = 2.5. 10 10 5 2 = ( 0 - 2 . 5 ) + (0 - 2. 5 ) 4(1 - 2.5)2 + ( 1- 2.5) + (2-2.5)" ( 2-2.5 ) 9 9 9 9 9 19 + (3 - 2:5)"+ ( 3- 2. 5) + (5- 2.5)" +(8 - 2. 5)2 9 5 = 0.6944+ 0. 6944+ 0. 25+0.25+ 0. 02777+0. 0272710.0277+ +0 02737 +069444+3.36111 5= 6 05 55 Sample Varona = 6:055.5 4) Variant deviation of The sample. = Jramona = JG.0555 = 2.4608 5) Based on the Calculation; the variably were normally distributed with a mean a 2.5 and a slandand devotion of 2.46 08 The mean is close to the standard deviation