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Solution : Given radius : 10 step1 : : 12 3 Complete revolutions cal= 3( 217 ) Q = Gu we know that the conical

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Solution : Given radius : 10 step1 : : 12 3 Complete revolutions cal= 3( 217 ) Q = Gu we know that the conical helix with auglow frequency a" on a cone of height "h and radius 'r' in a space curve given by the parametric equations are ; h- 2 x Cos (as ) = ) X = 12 - 3 ( 10 COS (GET 3 ) ) 12 starting &: 0. So, * = 19 - 0 12 10 Cos (0 ) y : hay fin (as ) 4 : 8 - 0 ( 101 8in ( 671 3 ) 12 4 :0 Gud 320 = ) 320 There fore, ( x, 4, 3) = ( 10, 0, 0) is taking in xy-plane.if it is not in 94 plane equations are ? x - 12 8 cocos ( 6712 ) 12 4 : 12- 8 10 fin ( Gu $3 ) 12 and 2 : 0 6 7 ( t ) = at t zo Y'( t ) = we know that curvature by - (vct ) x v"til

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