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Solve for all values of x in the given intervals: Cl 8) 8tan(:1:] + 11 = 19er 0 :1 mg 211' l:' b) 5602 (3:)

Solve for all values of x in the given intervals: Cl 8) 8tan(:1:] + 11 = 19er 0 :1 mg 211' l:' b) 5602 (3:) = 2tan2 (3-3) for 3: E R Cl C) 5302 {113) + 5302 (:13) 1 = 3 for 3E1

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