solve it with JAVA:

Write the output that is printed when the given method below is passed each of the following maps and lists as its parameters. Recall that maps print in a {key1=value1, key2=value2, ..., keyN=valueN} format.

Though hash maps usually have unpredictable ordering, for this problem, you should assume that when looping over the map or printing a map, it visits the keys in the order that they were added to the map or the order they are declared below. If a map calls put() on a key that already exists, it retains its current position in the ordering.

public static void collectionMystery5(ArrayList list1, ArrayList list2) {

 HashMap result = new HashMap();

 for (int i = 0; i < list1.size(); i++) {

 String s1 = list1.get(i);

 String s2 = list2.get(i);

 if (!result.containsKey(s1)) {

 result.put(s1, s2);

 } else if (!result.containsKey(s2)) {

 result.put(s2, s1);

 } else {

 result.put(s1 + s2, s1);

 }

 }

 System.out.println(result);

}

list1 = ["cat", "cat", "long", "long", "longcat"] list2 = ["mew", "purr", "cat", "cat", "purr" ]
list1 = ["a", "b", "a", "ab", "ab", "y", "abb"] list2 = ["b", "c", "b", "b", "c", "abb", "y" ]