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Solve the following differential equation with initial conditions: -2t y = et + 10et; y(0) = 1, y'(0) = 0. =e The solution is:
Solve the following differential equation with initial conditions: -2t y" = et + 10et; y(0) = 1, y'(0) = 0. =e The solution is: 5 4t -2t A. y = et + e 2 - 3t+ 5 4t B. y = -e2+ et - 2 == 87 c. y=4e2 + 16et - 6t + 19 D. yet + et - 1 E. y = e + e t - 2t+ 1/3
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Advanced Engineering Mathematics
Authors: Erwin Kreyszig
2nd Edition
471889415, 978-0471889410
