Solve the following initial value problem 1. 8 ( x - 4 ) + xy'=0 y(1 ) = 6 2 . - = 4
Solve the following initial value problem 1. 8 ( x - 4 ) + xy'=0 y(1 ) = 6 2 . - = 4 " - loy + 24 y ( 0 ) = 1 3. 4e = e - rx y (0) = 0 I is an arbitrary positive constant
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