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Solve the following questions results An instructor asked five students how many hours they had studied for an exam, with the accompanying Hours Studied Test

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Solve the following questions

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results An instructor asked five students how many hours they had studied for an exam, with the accompanying Hours Studied Test Grade 11 51 97 6 8 84 73 62 24) Figure the correlation coefficient (r) by filling in the blanks. Hours Studied Test Grade Cross X X-M. Products (X-M.) Y Y-My (Y-M.) ZY Z. ZY 0 -6.2 38.44 -1.72 51 11 -22.4 501.76 4.8 -1.39 2 39 23.04 97 23.6 556.96 1.46 6 -0.2 0.04 -0.06 84 10.6 112.36 0.66 ? 1.8 3.24 0.50 73 -0.4 -0.02 -0.0 6 -0.2 0.04 -0.06 62 -11.4 129.96 -0.71 7 E= 31 E= 64.8 E-367 2- 1301.2 My = 6.20 SD-=12.96 M,=? SD -? SD=3.60 SD-? Answer: r= 25) Determine the cutoff score(s) for this two-tailed test, using the .01 significance level. (Use a comma to separate answers as needed.) Answer: 26) Determine the test statistic. Answer: 27) Decide whether to reject the null hypothesis. Choose the correct answer below. A. Do not reject the null hypothesis. The results are inconclusive. B. Reject the null hypothesis. The results prove that the research hypothesis is true. C. Do not reject the null hypothesis. The results prove that the null hypothesis is true. D. Reject the null hypothesis. The results support the research hypothesis. Answer:QUESTION 1 Data on the number of occurrences per time period and observed frequencies follow. Use a = .05 to perform the goodness of fit test to see whether the data fit a Poisson distribution. What hypotheses are appropriate for this test? Number of Occurrences Observed Frequency 39 30 AWNO 30 18 3 Ho: The population has a Poisson distribution O H1: The population does not have a Poisson distribution Ho: The population has a Normal distribution O H1: The population does not have a Normal distribution Ho: The population does not have a Poisson distribution O H1: The population has a Poisson distribution Ho: The population has a Poisson distribution O H1: The population does not have a Poisson distribution3) The mgf for the Poisson distribution with rate A is ed(e-1). Suppose that X and Y are independent Poisson distributions with rates 3 and 5 respectively. Let W = X +Y and V = X - Y. (a) Write down the mof's of X and Y. (b) Find the mef of W. (c) Is W a Poisson distribution? If so, give the rate. (d) Find the mgf of V. (e) Is V a Poisson distribution? If so, give the rate.If a = 0.05, and p-value = 0.0002, what conclusion will you draw in a test of hypothesis? [Select the correct answer] Oa. Reject the alternate hypothesis O b. Reject the null hypothesis OCD Do not reject the null hypothesis Od. A Accept the alternative hypothesis

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