solve the following spectra. Can you explain how to do that step by step?

Problem 100 mpany 1600 IR Spectrum ICC solution 4000 3000 1600 1200 800 2000 V cm 183185 Mass Spectrum TWITTTTTT base peak UV Spectrum 2 258 (9, 42) 155/157 li M-18200 201 CH, OB 40 80 200 240 280 120 160 mie 13C NMR Spectrum (100.0 MHE. CDC, solution DEPT CH CH. CHA proton decoupled 200 160 120 80 40 0 & (ppm) 'H NMR Spectrum 200 M2 COCI, solution expansion 72 TMS 10 9 8 7 6 5 4 3 2 1 0 8 ppm Problem 99 IR Spectrum fiquidi 4000 3000 1200 800 2000 1600 v (cm) Mass Spectrum of base per UV Spectrum homas 262 nm (1090 2.5) solvent: ethanol C12H450 240 280 120 160 mle 13C NMR Spectrum 150,0 MHE. CDCI, solution 135 pon DEPT OCH proton decoupled 200 160 120 80 40 0 5 (ppm) TH NMR Spectrum 200 MHE. CDC, solution th TMS 10 9 8 7 6 4 3 2 1 0 & (ppm) of 100 188 Problem 98 IR Spectrum liquid 4000 3000 1200 800 2000 1600 V (cm) 147 Mass Spectrum 100F 80 139/141 % of base peak M 182/184 20 CHCI 40 80 200 240 280 120 160 mle 13C NMR Spectrum (500 MH. COCI, solution) Resolves into two sigrals at higher field strength DEPT CHI CH. CH Resolves into two signals at higher field strength solvent proton decoupled 200 160 120 80 40 08 (ppm) TH NMR Spectrum (200 MHE, COCI, solution) expansion expansion 2.75 2.5 ppm 15 10 ppm TMS 10 9 8 7 6 5 4 3 2 1 0 8 (ppm) Problem 97 pron IR Spectrum liquid fim 4000 3000 1600 1200 800 2000 V (cm) 100 57 Mass Spectrum UV Spectrum 12 80 60 A max 260 nm 109,9 25) of base perak 91 40: solvent methanol 201 M 140 C14H16 280 40 80 120 160 200 240 m/ 13C NMR Spectrum 1500 MG. CDCI, solution DEPT CHIO solvent proton decoupled 200 160 120 80 40 0 8 (ppm) 'H NMR Spectrum (200 H2, CDC, solution expansion 70 ppm TMS 10 9 8 7 6 5 4 3 2 1 0 8 (ppm) 97 of 100 186