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Solve the system by back substitution. 2x + 4y +z + 3w = 5 -y-6z - 2w = -8 5z + 5w = 10 4w

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Solve the system by back substitution. 2x + 4y +z + 3w = 5 -y-6z - 2w = -8 5z + 5w = 10 4w = 12 The solution set is {(100} (Type an integer or a simplified fraction.)

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