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Solve this problem thanks Consider constant magnetic eld, Bo, as shown below. A square loop of wire of resistance R, side length 6, and mass

Solve this problem thanks

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Consider constant magnetic eld, Bo, as shown below. A square loop of wire of resistance R, side length 6, and mass AI, is held above the magnetic eld, so that the bottom of the square loop is just outside of the magnetic eld at time t = 0. 4gh ' 1mb Q 3 >3 3 >3 3 >3 >3 .3 :3- >3- 3 Bu 3 3 >3 3 3 3 3 >3 3 3 >3 .3 >3 3 3 3 >3 3 3 3 >3 3 3 3 3 3 3 3 5 =3- 3 3 > 3- 3 >3 3 The loop is released from rest at t = l}, and allowed to fall under the force of gravity. For parts (a - d) assume that the loop has not fully entered the magnetic eld. (a) Derive an equation for the rate of change of the magnetic ux (Mm/(It in terms of Bu, 8 and 1.!(5). (b) Write an equation for the acceleration of the wire loop in terms of Bu, 5?, M, R, t) and universal constants of nature. (c) Find the velocity of the loop as a function of time. (Hint: For a function f{I), the differential equation f'($) = A + Bx), has the solution x) 2 C1833; bulb-- where C] is constant of integration.) (d) Suppose that the magnetic eld Bo is very weak, i.e. BE

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