Solve triangle ABC if ZA=43.1, a = 183.6, and b = 243.4. sin B (round answer to 5 decimal places) There are two possible angles B between 0 and 180 with this value for sine. Find the two angles, and report them so that /B is the acute angle. LB = and ZB2 = (round these and all remaining answers to 2 decimal places) Thus, two triangles satisfy the given conditions: triangle A BC and triangle A2B2C2. Solve the first triangle: ABC LC1 ==== and C1 = Solve the second triangle: A2 B2C2 LC2 == and c =