Solve using MATLAB

Consider the equilibrium reaction: A+2BC+D At equilibrium, it is known that KC=[A][B]2[C][D]=5 And that [A]=1[B]=22[C]=1+[D]=2+ Where is the extent of reaction in moles. Physically, this means that there are initially 1 mole of A,2 moles of B,1 mole of C, and 2 moles of D. a. A senior engineer suggests that the above equation should be rearranged to: KC(1)(22)2(1+)(2+)=0=f() Rather than to: KC(1)(22)2(1+)(2+)=0=f() Why did the senior engineer suggest this? In other words, why is the first equation "better" than the second? b. What are logical bounds for ? c. Using a bounded root finding method and the bounds from 2b, determine when KC=5. Use at least 100 iterations. d. KC can change with temperature. This will then change . Generate a plot of KC versus .KC should go from 0.01 up to 10 in increments of 0.01. Note: if a few points are discontinuous, that's okay