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solving the a, b and c on matlab. thank you a. 3t48(t-1) b. to(t - 2)dt c. t*8't-3) Home Search Bookshelf Settings OD @ BT

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a. 3t48(t-1) b. to(t - 2)dt c. t*8't-3) Home Search Bookshelf Settings OD @ BT dt la Q Q Page 12 Example 1.8 Evaluate the following expressions: a. 3+*8(t-1) b. sto(t - 2)dt c. t8(t - 3) Solution: a. The sampling property states that f(t)&(t-a) = f(a)(t-a) For this example, f(t) = 3t" and a = 1. Then, 3+*8(t - 1) = {3+* - ,}$(t - 1) = 38(t - 1) b. The sifting property states that f(t):(t - a)dt = f(a). For this example, f(t) = t and a = 2. Then, to(t - 2)dt = f(2)=t|.- 2 = 2 c. The given expression contains the doublet; therefore, we use the relation f(t)8'(t-a) = f(a)8'(t-a) - f'(a)(t-a) Then, for this example, e ENG 08/0 a. 3t48(t-1) b. to(t - 2)dt c. t*8't-3) Home Search Bookshelf Settings OD @ BT dt la Q Q Page 12 Example 1.8 Evaluate the following expressions: a. 3+*8(t-1) b. sto(t - 2)dt c. t8(t - 3) Solution: a. The sampling property states that f(t)&(t-a) = f(a)(t-a) For this example, f(t) = 3t" and a = 1. Then, 3+*8(t - 1) = {3+* - ,}$(t - 1) = 38(t - 1) b. The sifting property states that f(t):(t - a)dt = f(a). For this example, f(t) = t and a = 2. Then, to(t - 2)dt = f(2)=t|.- 2 = 2 c. The given expression contains the doublet; therefore, we use the relation f(t)8'(t-a) = f(a)8'(t-a) - f'(a)(t-a) Then, for this example, e ENG 08/0

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