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Someone can let me know why I in KIO3 is x+1-6= 0 , in KI is x+1=0 and I2 is x+x=0? KI 03 (aq.)
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Someone can let me know why I in KIO3 is x+1-6= 0 , in KI is x+1=0 and I2 is x+x=0?
KI 03 (aq.) + 5 KI (aq) + 6HCl 3 Iz(s) + 6 kol (aq) + 3H20. Here, oxidation state of I in kI03 at 1-6zo +5 In KI a + 1 zo >> =-1 In I2 2+20 2 20Step by Step Solution
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Chemical Principles
Authors: Steven S. Zumdahl, Donald J. DeCoste
7th edition
9781133109235, 1111580650, 978-1111580650
