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Sorry for the multiple questions!!!! Please HELPPP 6. [-/1 Points] DETAILS 0/6 Submissions Used MY NOTES Suppose there is a rectangle with length _ and

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Sorry for the multiple questions!!!! Please HELPPP

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6. [-/1 Points] DETAILS 0/6 Submissions Used MY NOTES Suppose there is a rectangle with length _ and width W (W S L) (in feet) that has perimeter 72 feet. (a) Find L and W such that the rectangle has maximum area. L : W = ft (b) Find the maximum area (in square feet) of the rectangle. sq ft Submit Answer 7. [-/1 Points] DETAILS 7. 0/6 Submissions Used MY NOTES Suppose there is a rectangle with length L and width W (W S L) (in inches) that has an area of 225 square inches. (a) Find L and W for the rectangle with minimum perimeter. L= in W = in (b) Find the minimum perimeter (in inches) of the rectangle. in Submit Answer 8. [-/1 Points] DETAILS 0/6 Submissions Used MY NOTES A javalina rancher wants to enclose a rectangular area and then divide it into four pens with fencing parallel to one side of the rectangle (see the figure). They have 840 feet of fencing available to complete the job. What is the largest possible total area (in square feet) of the four pens? sq ft Submit Answer 9. [-/1 Points] DETAILS 0/6 Submissions Used MY NOTES A rectangular cardboard box is made with a square base and an open top. The box has a volume of 108 cubic centimeters. (a) Find the dimensions (in cm) of the box that uses the least cardboard. height of the box cm length of the side of the base cm (b) Find the least amount of cardboard (in cm2) needed to construct the box. cm 2 Submit Answer 10. [-/1 Points] DETAILS 0/6 Submissions Used MY NOTES An aluminum can is to be constructed to contain 2,700 cubic centimeters of liquid. Let r and h be the radius of the base in centimeters and the height of the can in centimeters respectively. (a) Find the height and radius (in cm) of the can that uses the least amount of aluminum. (Round your answers to four decimal places. Hint: The volume V of the can in cubic centimeters is given by V = Arch and the surface area A of the can in square centimeters is given by A = 2rrh + 2nr2.) h = cm r = cm (b) Find the least possible amount (in cm ) of aluminum needed to construct the can. (Round your answer to four decimal places.) A = cm 2

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