Specific ld gives us precise info-otherwise we use a Cost Flow Assumption Perpetual Specific Identification (need to be able to identify which units were sold at the point of purchase) Date Purchases Sales Cost of Sales Balance in Inventory 100 550 each - 5.000 3/1 Beg Inv 375 Purchase 400 $55 cach $22.000 500 3:9 Sold 420 u 420 - $85 ear $35,700 2 585 each u S60 cach- 3/18 Purchase 100u SAD= 5.000 400 y $55=22.000 271000 80 $50 = 4,000 20 @ $50 = 1,000 340 @ $55= 18.70060 @ $55 = 3.300 420 22.700 80 4300 20 50 = 1.000 60 @55= 3.300 $ 11,500 120 602 7.200 20 50 1.000 50 $ 55= 3.300 120 60=7200 $23.400 200 @ 62 = 12.400 $7.200 00 200 m 2 62 cach - 3/23 Purchase 12.400 Sold 160 @ $95 160 395 cach 15,200 40 $ 60- 2.400 20 50 = 1.000 120 @ 62 - 7.440 60 55= 3,300 160 054 80 60 = 4,800 9.840 Poe 62 = 4.960 100 14.060 240 Specific ld gives us precise info-otherwise we use a Cost Flow Assumption Perpetual Specific Identification (need to be able to identify which units were sold at the point of purchase) Date Purchases Sales Cost of Sales Balance in Inventory 100 550 each - 5.000 3/1 Beg Inv 375 Purchase 400 $55 cach $22.000 500 3:9 Sold 420 u 420 - $85 ear $35,700 2 585 each u S60 cach- 3/18 Purchase 100u SAD= 5.000 400 y $55=22.000 271000 80 $50 = 4,000 20 @ $50 = 1,000 340 @ $55= 18.70060 @ $55 = 3.300 420 22.700 80 4300 20 50 = 1.000 60 @55= 3.300 $ 11,500 120 602 7.200 20 50 1.000 50 $ 55= 3.300 120 60=7200 $23.400 200 @ 62 = 12.400 $7.200 00 200 m 2 62 cach - 3/23 Purchase 12.400 Sold 160 @ $95 160 395 cach 15,200 40 $ 60- 2.400 20 50 = 1.000 120 @ 62 - 7.440 60 55= 3,300 160 054 80 60 = 4,800 9.840 Poe 62 = 4.960 100 14.060 240