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Spring 2022 Home Announcements Grades Course Evaluations U E E tarletonjnstructurecom G u Dashboard ~23! Quiz: Exam 3 Question 13 2 pts Question 4- Intro

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Spring 2022 Home Announcements Grades Course Evaluations U E E tarletonjnstructurecom G u Dashboard ~23! Quiz: Exam 3 Question 13 2 pts Question 4- Intro Data indicates that adolescent girls tend to experience a drop in self-esteem. To evaluate this result, a researcher obtains a sample of N = 16 adolescent girls, all 13 years old. A self-esteem measure is administered to each participant and the average score for the sample is X = 68 with $5 = 3840' It is known that the mean self-esteem score for the population of pre-teen girls is 75. For this sample, the standard deviation is and the standard error is Question 14 3 pts Question 4A Data indicates that adolescent girls tend to experience a drop in self-esteem. To evaluate this result, a researcher obtains a sample of N = 16 adolescent girls, all 13 years old. A self-esteem measure is administered to each participant and the average score for the sample is 3? = 68 with $5 = 3840. It is known that the mean self-esteem score for the population of preteen girls is 75. A) Compute a 95% condence interval for u, the population mean self-esteem score for 13-year old girls. .,,u,~, ,,,,,u, a,\" l tarleton.instructure.com C + 88 Dashboard Quiz: Exam 3 Spring 2022 For this sample, t*df = Home Announcements The 95% CI = ( Grades NOTE: Report t*df exactly as it is in the PsyStat calculator. Report the confidence interval to two numbers Course Evaluations after the decimal place (eg: 1.1 1, 2.22). Eh D Question 15 1 pts ? Question 4A- t*df Work In the PsyStat calculator: Distribution: [ Select ] A df: [ Select ] Find area: [ Select ] [ Select ] b: [ Select ]tarleton.instructure.com C + 88 Dashboard Quiz: Exam 3 D Spring 2022 Question 16 2 pts Home Announcements Question 4B- t and p Grades Data indicates that adolescent girls tend to experience a drop in self-esteem. To evaluate this result, a researcher obtains a sample of N = 16 adolescent girls, all 13 years old. A self-esteem measure is Course Evaluations administered to each participant and the average score for the sample is X = 68 with SS = 3840. It is known that the mean self-esteem score for the population of pre-teen girls is 75. Eh B) Perform a hypothesis test to decide whether the mean self-esteem score for adolescent girls is significantly different from the mean self-esteem score for pre-teen girls. t = ? p = NOTE: Record the p-value exactly as it is in the PsyStat calculator. Record the t-statistic to two numbers after the decimal place. D Question 17 1 pts Question 4B- Work for p-value In the PsyStat calculator: Distribution: [ Select ] df: [ Select ]Spring 2022 Home Announcements Grades Course Evaluations u Dashboard U E E '(arletonjnstructure'com CD 0 Find area: l Select l 0 a: [ Select] 0 b: [Select ] ~33! Quiz: Exam 3 Question 18 2 pts Question 4B Hypothesis Decision 4 For these data, Ho: [1 [59'9\"] 6 175 and H1:,u [59'5\"] 75. As p [Select] c 005, our data are [59'5\"] 9 under the null 9 the null hypothesis. There hypothesis. Thus, we [Select] [56'9\"] a signicant difference in self-esteem between adolescent girls and the general population of pre-teen girls. Question 19 1 pts tarleton.instructure.com C + 88 Dashboard Quiz: Exam 3 D Question 19 1 pts Spring 2022 Home Question-4C Announcements C) Compute and interpret a Bayes factor for the model (either Ho or H1) with the best predictive Grades adequacy for Question 4. Course Evaluations We found a Bayes factor of BF [ Select ] [ Select ] Eh which means that the observed data are approximately [ Select ] times more likely under H [ Select ] * than H [ Select ] ? D Question 20 1 pts Question 4C- Work for Bayes factor In the PsyStat Bayes factor calculator: Test: [ Select ] Design: [ Select ] Predicted direction: [ Select ] t-statistic: [ Select ]Spring 2022 Home Announcements Grades Course Evaluations U E E tarletonjnstructure'com C u Dashboard '33! Quiz: Exam 3 womb... , 0 Predicted direction: [59'9\"] 0 t-statistic: [59'5\"] 0 Sample size 1: [59'9\"] Sample size 2: [seledl 9 (if needed) Prior probability of null: 05 Question 21 1 pts QM D) Compute and interpret the posterior model probability for the winning model chosen in part C. Our Bayes factor updated our previous 1-to-1 odds, resulting in the winning model having a posterior model probability of p(H[O]|data) = [55'9\"] 9 . In summary, these data provide [Select] evidence in favor of H [Select] ; that is, [Select] 3 had 4 [Select] 9 on [Select] Spring 2022 Home Announcements Grades Course Evaluations U E E tarleton.instructure.com G u Dashboard ~23! Quiz: Exam 3 Question 22 8 pts Question 4- Paper Work Upload the work you have done on paper for question 4 here. Here is the breakdown of points for the work of each problem: Standard deviation formula/ answer: 2 points Standard error formula/ answer: 2 points Condence interval formula/ answers: 2 points t-statist'ic formula/ answer: 2 points Uplad Choose a File Question 23 2 pts Question 5- Intro A sample of N = 25 individuals is selected from a population with a mean of 82.5' A treatment is administered to the individuals in the sample, and, after treatment, the sample has a mean of} = 84 and $5 = 216. For this sample, the standard deviation is and the standard error is Spring 2022 Home Announcements Grades Course Evaluations u Dashboard U E E tarleton.instructure.com G Question 23 2 pts '33! Quiz: Exam 3 Question 5- Intro A sample of N = 25 individuals is selected from a population with a mean of 82.5' A treatment is administered to the individuals in the sample, and, after treatment, the sample has a mean of} = 84 and $5 = 216. For this sample, the standard deviation is and the standard error is Question 24 3 pts Question 5A A sample of N = 25 individuals is selected from a population with a mean of 82.5. A treatment is administered to the individuals in the sample, and, after treatment, the sample has a mean of 3? = 84 and $5 = 216. A) Compute a 95% condence interval for [4, the population mean for the treatment group. For this sample, t*df The 95% C|=(

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