SSTR 6,750 H 0 1 2 3 4 SSE 8,000 H a at least one mean is different n T 20 The null hypothesis is to be tested at the 5 level of significance The p value is

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SSTR = 6,750 H 0 : 1= 2= 3= 4 SSE = 8,000 H a : at least one mean is different n T =

SSTR = 6,750	H₀: ₁₌₂₌₃₌₄
SSE = 8,000	H_a: at least one mean is different
n_T = 20

The null hypothesis is to be tested at the 5% level of significance. The p-value is

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