standing fo O V(L) Nopl Noo N The figure shows a pV-diagram for 1.8 g of helium gas (He) that undergoes the thermodynamic process from states 1 - 2 - 3. The ideal gas constant R = 0.0821 L. 18 atm/mol . K, the atomic weight of helium is 4.0 g/mol. How many moles of helium gas is this? 0.25 mol 0.45 mol 2.22 mol O 6.022 x 1023 molV(L) O V V 3 The figure shows a pV-diagram for 1.8 g of helium gas (He) that undergoes the thermodynamic process from states 1 - 2 - 3. The ideal gas constant R = 0.0821 L . atm/mol . K, the atomic weight of helium is 4.0 g/mol. What is the initial volume Vy (in liters) in state 1 before the process begins? 5.73 L O 28.2 L 0.683 L 11.5L0 V(L) V V 3 The figure shows a pV-diagram for 1.8 g of helium gas (He) that undergoes the thermodynamic process from states 1 - 2 - 3. The ideal gas constant R = 0.0821 L. atm/mol . K, the atomic weight of helium is 4.0 g/mol. What is the final volume V3 (in liters) in state 3 after undergoing an isochoric process from state 1 to 2, and an isothermal expansion from state 2 to 3? 5.73 L 22.4 L O 17.2 L 12.4 LListen P 12 P2 N 657C Isothermal 14 15 17 18 2.0 37.C - 20 atm 1 V(L) O VI V3 O V-diagram for 1.8 g of helium gas (He) that undergoes the D = 0 0821 1