Start with a circle of radius r=12. Form the two shaded regions pictured below: (2(6) has an arc and two straight line sides and t(6) is a right triangle. Note that the areas of these two regions will be functions of 9; r is xed in the problem. (a) Find a formula for Area(c(6'))= (d) (Iii{'13 Area {t (3)}: (e) (El1.13} [Area(c(6))/Area(t(l9))]= |:|