Step 1 The terms of the series E (-1)? 1 decrease as n - co and lim 0 n = 1 010" n - 00 n10" 0 Step 2 Therefore, by the Alternating Series Test, (-1)" convergent V convergent n = 1 010? Step 3 1 We know that the remainder R,, will satisfy IR,| = D, + 1 = (n + 1)107 + 1' We must make n large enough so that this is less than 0.0001. Rounding to five decimal places, we have by = , b3 = and bA = Submit Skip (you cannot come back)