STEP 3 Add a jumper wire to the circuit, in parallel with D2, as illustrated in this schematic: R1 330 Q P33 5 V Question 3 2 pts In Step 3, what is the potential difference across D2 after the jumper wire is connected? O Approximately 2.7V, because my LED is still lit and the jumper wire is not properly connected. O Approximately 5V, because I am somehow measuring across the whole path instead of just D2. O OL, because I am not using the correct meter settings. O 0.0 mV, because the LED is not lit and the component leads are connected to each other by the jumper wire. D Question 4 2 pts After the jumper wire is connected across D2 in Step 3, what is the NEW potential at the high side of D2, in reference to ground? Approximately +2.7V because nothing has changed in the circuit. O 0.0 mV, because that location is now connected directly to ground. O Approximately +5V, because I am measuring to high potential instead of ground. O Approximately 2.7V, because the forward voltage of the LED does not change.Question 5 2 pts In Step 3, was the potential at the high side of D2, 'pulled' higher or lower, in reference to ground, by the jumper wire? O The potential was not pulled higher or lower, because it remained unchanged. O Higher. This is a pull-up connection. O Lower. This is a pull-down connection. O The potential was not pulled, it was pushed. I did not read the title of this lab assignment. Question 6 2 pts In Step 3, what was the voltage across R1 after D2 was shorted? 2.98 v How much current is flowing through the circuit in this step? 8.39 mA