step by step,hand calculation."DONT GVE SUGGESTION,WRITE DOWN THE ALL ANSWER,EQUATIONS... OR I WILL COMPLAIN BOUT YOU!!! """THIS IS SECOND TIME THAT O HAVE SEND THIS QUESTION TO CHEGG!!!"

1) A 0.6m wide heat-treated process line is kept at 600C, its emissivity is 0.8 and its back surface is adiabatic. In order to limit radiative heat loss to the environment, it has been suggested to use radiation shields with a height of 0.3 m and an emissivity of 0.10 on both sides. The back surfaces of radiation shields are adiabatic. The heat transfer coefficient on the production line's upper surface and the inner surfaces of the radiation shields is given as 10W/m2K. The environmental temperature is 20C. According to this; a) Total heat loss due to radiation and convection when a radiation shield is not used, (For unit length of the process line, W/m) b) Calculate the heat loss and heat shield temperatures when a radiation shield is used. 2) Based on the heater power (W/m) calculated for the situation where no radiation shield is used in the previous question, calculate the surface temperature that will be reached if a shield is used for the same heater power (it will be a value greater than 600C )