Student(snum: integer, sname: string, major: string, level: string, age: integer) Class(name: string, meets at: string, room: string, fid: integer) Enrolled(snum: integer, cname: string) Faculty(fid: integer, fname: string, deptid: integer) The meaning of these relations is straightforward; for example, Enrolled has one record per student-class pair such that the student is enrolled in the class.

Write the following queries in relational algebra NOT SQL. No duplicates should be printed in any of the answers. What is the relational algebra from the question below. I already have the SQL and need it in relational algebra.

6. Find the names of faculty members for whom the combined enrollment of the courses that they teach is less than five.

SELECT DISTINCT F.fname

FROM Faculty F

WHERE 5 > (SELECT COUNT (E.snum)

FROM Class C, Enrolled E

WHERE C.name = E.cname

AND C.fid = F.fid);

8. For all levels except JR, print the level and the average age of students for that level.

SELECT S.level, AVG(S.age)

FROM Student S

WHERE S.level <> JR

GROUP BY S.level;