Question
Studies suggest that class participation of students is vital in improving the overall performance of students in their subjects. To estimate this relationship the subject
Studies suggest that class participation of students is vital in improving the overall performance of students in their subjects. To estimate this relationship the subject coordinator of BUS1BAN, using the data from prior semester, examines the effect of class participation marks (x) on the marks of other assessments (y). The following excel output resulted after running linear regression between variables x and y:
INSTRUCTIONS: You are required to answer the following questions by selecting the best option from the drop down window or by typing your answer in the box next to the question:(10 marks)
- The relationship between the variable x and y isAnswerpositivenegative,
- The values of the intercept and slope coefficients areAnswer20.4413 and 4.9978 respectively0.6745 and 0.4549 respectively0.4549and 0.6745 respectively4.9978 and 20.4413 respectively,
- The least square line from the above output isAnswer=20.4413x+4.9978x=20.4413+4.9978x=20.4413+4.9978=20.4413+4.9978x,
- The value of the coefficient of determination isAnswer20.44130.67454.99780.4549,
- Select appropriate interpretation for slope coefficient:AnswerIf the class participations marks increase by 1, the marks in other assessments increase by 4.9978 on average.If x increases by 0.4549, y also increases by 4.9978 on average.If the marks in other assessments increase by 1, the class participations marks increase by 4.9978 on average.,
- Calculate the coefficient of correlation and type your answer in this box (round it up to 4 decimal places): =Answer
In order to determine whether there is enough evidence to conclude that a linear relationship exists between the variable y and variable x we perform hypothesis testing at 5 percent significance level. Answer the following questions:
- The null hypothesis isH0:1H0:1Answer 0.05> 0=0.05=0,
- The alternative hypothesis isH1:1H1:1Answer 0.05 0 0.05< 0,
- As per excel output, the value of t-statistic for this test isAnswer23.7355None of the other two options12.9161,
- The decision rule is to rejectH0H0ifAnswerp-value < significance levelBoth the two options are correctp-value > significance level,
- Given the observed value of the test statistic, we decide toAnswermaintain the nullreject the null.
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