Using the substitution: u=z+3z-6. Re-write the indefinite integral then evaluate in terms of u. -3x-6 [((-)2 + (-)) + -6dz = Note: answer should be in terms of u only Back substituting in the antiderivative you found in Part 1. above we have [((-) + (-))e+-6 dz = Note: answer should be in terms of I only