Sue's grade in her math class is related to the number of hours she studies. The rate of change of her grade, G(t), is proportional to (100 - G), where t is measured in hours and G(t) is her grade after t hours of study. The highest grade is a 100. 6(0) = 60, meaning she could get a 60 without any studying. After 10 hours Sue's grade would be an 80. How many hours would Sue need to study to get an A, which is a 90 or better? Round your answer up to the nearest hour. 0 12 O 20 O 25 030 Newton's heating-cooling law states that the rate of change in the temperature, H, is proportional to the difference between the object and the surrounding temperature. Let H(t) be the temperature of the object being heated and S be the surrounding temperature. A cold object at 35 degree is placed in an oven at 350 degrees Fahrenheit and after 30 minutes the object is 100 degrees. Write and solve the differential equation which describes the temperature of the object over time, where time is measured in hours. 0 H(t) = 350 7 100.1504622t 0 Hot) : 350 315e-0-462m 0 Hot) : 100 3560-4622't O H(t) = 100 7 315.504622t Auto saved at: 20:41 If investment A has continuously compounded interest and an annual return of 2%, and Jane has $100 after 5 years, how much money will she have after 8 years? Round to the nearest dollar. 0 106 O 115 O 120 O 140 A population of wasps, W, are growing at the rate proportional (2000 - W). After 10 days the wasps were counted and there were 300 wasps. After 15 days there were 600 wasps. When will there be 1999 wasps? Round to the nearest day. 0 400 O 250 O 202 O 100 The rate of change of R is inversely proportional to R(x) where R > 0. If R(0) = 25, and R(2) = 10, find x, such that R(x) = 16. 0 -3 O -2.893 O 1.406 0 4A rate of change of H is given by g : 1::(15 + H). When t = 0, H = 20. When t = 2, H = 50. Solve for k where H > -15. O 0.31 O 1.208 O 2.282 O 3.282