Suppose 315% = 3 $5 + 2 m2 _ |n differential form this is y5 dy : (32:5 + 2:122) do: Integrating both sides gives: fydy=f335+2$2dm We can see that the problem has been separated into a problems with all the m's on one side, and all the ys on the other. Now (without constants of integration) - ny' dy = @ D .f3$5+23:2d$: gm. So we conclude that: with a constant of integration, y =33:l +4133 + 0'. Note that this solves the original differential equation implicitly - instead of y as a function of 1: we get a relation satisfied by :1: and y