Question
Suppose a 98% confidence interval is neededfor the average weight of these cans of creamed corn is needed, because someone thinks the average is not
Suppose a 98% confidence interval is neededfor the average weight of these cans of creamed corn is needed, because someone thinks the average is not the 16 ounces it was supposed to be. If this interval is to have a margin of error of0.02 oz, how many data points will be needed for the new sample?
Suppose that cans of creamed corn were supposedto beproduced so that the average net content weight is 16.00 ounces per can.However, a sample of 64 weights yields an average of15. 953 ounces and a deviation of 0.0762 ounces. Use this sample information to create a 98% confidence interval for the population mean(round to the nearest thousandth of an ounce)
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