Suppose a population has a mean weight of u = 79.676 kg and a standard deviation of 0:22.4943. For samples of size n= 36, A sample of size n=36 is taken. Approximate the weight that lies at the 95th percentile of the sampling distribution. (hint: use number 1, the equation 7 = \"at\"? and the fact that the 95th percentile of the standard normal distribution is approximately 2 = 1.645). Round your estimated 9'5th percentile average weight to two decimal places