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Suppose f (m) = 3:3 + 62:2 63:15 + 7. Find the absolute extrema of f on each of the following intervals. Note: Enter NONE
Suppose f (m) = 3:3 + 62:2 63:15 + 7. Find the absolute extrema of f on each of the following intervals. Note: Enter NONE wherever there are no absolute extrema. (a) Interval = [8, 0]. Absolute maximum: Absolute minimum: (b) Interval = [5, 4]. Absolute maximum: Absolute minimum: (c) Interval = [8, 4]. Absolute maximum: Absolute minimum: Suppose f(:r:) = (m 1)(a: 7)3 -I- 7. Find the absolute extrema of f on each of the following intervals. Note: Enter NONE wherever no absolute extrema exist. (a) Interval = [1, 4]. Absolute maximum: Absolute minimum: (b) Interval = [1, 8]. Absolute maximum: Absolute minimum: (0) Interval = [4,9]. Absolute maximum: Absolute minimum: After his graduation, a Wilfrid Laurier University student departed Earth to find work on Mars. A model for the velocity (in feet per second) of his spaceship from liftoff at t : 0 seconds until the rocket boosters were jettisoned at t : 57.4 seconds is described by: v(t) = 0301659000153 0.08811)? + 25.41: + 3.51. To 3 decimal places, determine the shuttles absolute maximum and absolute minimum acceleration: Maximum Acceleration: ft/32 Minimum Acceleration: ft/32 Recall: Acceleration is defined as a(t) : v'(t)
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