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Suppose, for a random sample selected from a normally distributed population, x = 74.40 ands = 7.2 Round your answers to 2 decimal places. a.

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Suppose, for a random sample selected from a normally distributed population, x = 74.40 ands = 7.2 Round your answers to 2 decimal places. a. Construct a 95% confidence interval for / assuming n = 16. to b. Construct a 90% confidence interval for / assuming n = 16. to i Is the width of the 90% confidence interval smaller than the width of the 95% confidence interval calculated in part a? c. Find a 95% confidence interval for / assuming n = 25. to Is the width of the 95% confidence interval for / with n = 25 smaller than the width of the 95% confidence interval for /with n = 16 calculated in part a?Current Attempt in Progress The high price of medicines is a source of major expense for those seniors in the United States who have to pay for these medicines themselves. Arandom sample of 1400 seniors who pay for their medicines showed that they spent an average of $4900 last year on medicines with a standard deviation of $700. Make a 90% condence interval for the corresponding population mean. Round your answers to cents. :5. m. eTextbook and Media Save for Later Attempts: 0 of 5 used A random sample of 250 observations selected from a population produced a sample proportion equal to 0.89. Round your answers to 3 decimal places. a. Make a 90% confidence interval for p. to i b. Construct a 95% confidence interval for p. to i c. Make a 99% confidence interval for p. to i d. Does the width of the confidence intervals constructed in parts a through c increase as the confidence level increases

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