Suppose F(t) is an antiderivative of t5. Then F'(t)= According to the Second Fundamental Theorem of Calculus, :12 / tsdt = . Answer using the function F. 1 Use your answers above or the First Fundamental Theorem of Calculus to find 2': t5dt = data 1 See Example 1 page 238 for a similar problem. Suppose F(t) is an antiderivative of 3% . Then F'(t)= According to the Second Fundamental Theorem of Calculus, :1: t5/4 / dt = . Answer using the function F. 3 W2 +17 Use your answers above or the First Fundamental Theorem of Calculus to find d 2: t5/4 dt : d9: 3 \\3/t2+17 See Example 2 page 238 for a similar problem. Suppose F(t) is an antiderivative of 133,113 t sec2 t. Then F'(t)= According to the Second Fundamental Theorem of Calculus, 4 / tan3 t sec2 t dt = . Answer using the function F. :1: Use your answers above or the First Fundamental Theorem of Calculus to find 4 tan3 t sec2 t dt = dm 3 See Example 3 page 238 for a similar problem. Suppose F(t) is an antiderivative of 6:2. Then F'(t)= According to the Second Fundamental Theorem of Calculus, :35 f at2 dt = . Answer using the function F. 1 Use your answers above to find 0! $5 a 1 Hint: You will have to use the chain rule. 3:2 dt = An object at the origin at time t = 0 has velocity measured in meters per second, 15+ 25 if 0