Question
Suppose I have a Pt disk electrode in a solution of Cu 2+ plus 0.1 M KCl versus a saturated calomel electrode (ESCE = 0.242
Suppose I have a Pt disk electrode in a solution of Cu2+ plus 0.1 M KCl versus a saturated calomel electrode (ESCE = 0.242 V). If the E1/2 for Cu2+ reduction is at 0.100 V vs. SCE, what would the E1/2 be if I added 0.10 M NH3 and the following reaction occurred:
Cu2+ + 4NH3 ----------- Cu(NH3)42+ K = 1.1 x 1013
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Organic Chemistry
Authors: Joseph M. Hornback
2nd Edition
9781133384847, 9780199270293, 534389511, 1133384846, 978-0534389512
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