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Suppose I have a std::vector A . This vector has only values in the range of 0 to A . size ( ) , inclusive.

Suppose I have a std::vector A. This vector has only values in the range of 0
to A.size(), inclusive. For example, if there are 5 values in A, then the only values it can
have are {0,1,2,3,4,5}, although not necessarily in that order. Duplicate values might be
present too.
Obviously, at least one value is missing. Using O(n) worst-case time and O(n) space, where
n is A.size(), determine which value(s) are missing from the vector. You may not use any
standard library data structure other than std::vector. For full credit, you should not use
any more space than is strictly necessary to solve this problem, other than basic overhead
(a std::vector is still preferred to a C-style array and wont be penalized, even though it
does take some additional space, for example). Justify the running time and space of your
approach.
3. Repeat the previous problem, but with the added information that now, A has no duplicates.
Can you find the missing element in O(n) time with O(1) space

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